작성일 : 16-03-16 01:41
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[JQuery] 동적 select load
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글쓴이 :
조형래
 조회 : 4,794
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<script src="/js/jquery-1.8.3.min.js"></script>
<script type="text/javascript">
$(document).ready(function () {
$.rian_project_code_selecct_<?php echo $date_y?>_<?php echo $month_s?>_<?php echo $day?> = function(aa) {
$("#<?php echo $date_y?>_<?php echo $month_s?>_<?php echo $day?>").load('./rian_project_code_select.php', { project: aa });
};
});
</script>
<select name="porject" onchange="javascript:$.rian_project_code_selecct_<?php echo $date_y?>_<?php echo $month_s?>_<?php echo $day?>(this.value)">
<option></option>
<?php
$sql_one = " select * from g5_write_project where wr_10='' order by 1 asc";
$sql_one2 = sql_query($sql_one);
while ($sql_row = sql_fetch_array($sql_one2)){
?>
<option value="<?php echo $sql_row["wr_subject"];?>">
<?php echo $sql_row["wr_subject"];?>
</option>
<?php
}
?>
</select>
<span id="<?php echo $date_y?>_<?php echo $month_s?>_<?php echo $day?>"></span>
----------------------
<select>
<?php
include_once('./_common.php');
include_once("./include/dbconnect.php");
$project = $_REQUEST["project"];
$sql = "select distinct code from rian_project_code where project = '$project' order by code asc";
$sql_one2 = sql_query($sql);
while ($sql_row = sql_fetch_array($sql_one2)){
?>
<option value="<?php echo $sql_row["code"];?>">
<?php echo $sql_row["code"];?>
</option>
<?php
}
?>
</select>
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